Algorithm · Airbnb · Hard
Examples Example 1 Example 2 Requirements Given the heads of two ListNode chains; either chain might include a loop. Produce a boolean result: return True when the lists have one or more physical nodes in common, and False when they have none. As an optional extension, return the earliest shared node whenever the result is True. Notes Account for boundary conditions such as an empty list on either side, a one-node list, lists with an identical head, and lists that traverse…
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